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  1. A noiseless 3 KHz channel can transmit binary at the rate __________ .

  2. A.
    12000 bps
    B.
    10000 bps
    C.
    6000 bps
    D.
    3000 bps

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    Answer : Option C

    Explanation :

    Maximum data rate for noiseless channel is given by Nyquist Theorem

    = 2H log2 V bits/sec

    V - discrete levels (Here Binary i.e. 2)

    H - Bandwidth

    Maximum data rate = 2H log2 V

    = 2(3 KHz) log2 2 = 2 x 3 x 103 x 1

    = 6 x 103 = 6000 bps.


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