Home / ECE / Exam Questions Paper :: Discussion

Discussion :: Exam Questions Paper

  1. The current i(t) through a 10 Ω resistor in series with an inductance is given by i(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) Amperes. The RMS value of the current and the power dissipated in the circuit are

  2. A.
    41 A, 410 W respectively
    B.
    35 A, 350 W respectively
    C.
    5 A, 250 W respectively
    D.
    11 A, 1210 W respectively

    View Answer

    Workspace

    Answer : Option C

    Explanation :

    Power = I2R = 25 X 10 = 250 Watts.


Be The First To Comment