The cut off voltage for JFET is 5 V. The pinch off voltage is __________ .
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Answer : Option D
Explanation :
For JFET
ID = IDSS (1 - VGS/Vp)2
0 = (1 - VGS/Vp)2
∴ VGS = VP
∴ Vp = 5 V.
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