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  1. Find the value of K and velocity constant Kv so that the maximum overshoot in the unit step response is 0.2 and the peak time is 1 sec.

  2. A.
    12.37, 0.175
    B.
    12.86, 2.175
    C.
    11.36, 1.175
    D.
    1.86, 0.175

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    Answer : Option A

    Explanation :

    ζ2 = 0.259(1 - ζ2) = 0.259 - 0.259ζ2

    1.259ζ2 = 0.259

    ζ2 = 0.206

    ζ = 0.45

    ω2n = K

    ωn = K and 2ζωn = 1 + KKv

    ωn = K

    K = ω2n

    K = 12.37

    1 + 12.37Kv = 2 x 0.45 x 3.52

    Kv = 0.175 .


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