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  1. For the given phase lead network, the maximum possible phase lead is

    2. A.
    sin-1
    B.
    30°
    C.
    45°
    D.
    60°

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    Answer : Option B

    Explanation :

    The maximum phase lead is given by,

    sin φm =

    Where

    Hence sin φm =

    Hence φm = 30°.

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