The VTH at terminals A and B is equal to,
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Answer : Option B
Explanation :
Apply KVL to loop 1
5V - 3I1 - 2(I1 - I2) - 5V = 0
∴ I2 = 0
5 - 3I1 - 2I1 - 5V = 0
∴ I1 = 0
∴ VAB = 5V.
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