Discussion :: Exam Questions Paper
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Consider the frequency modulated signal 10 cos (2p x 105t + 5 sin (2p x 1500t) + 7.5 sin (2p x 1000t) with carrier frequency of 105Hz. The modulation index is
Answer : Option B
Explanation :
Total frequency deviation = 5 x 1500 + 7.5 x 1000 = 15000
Thus modulation index = .
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