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  1. In the following network, the switch is closed at t = 0 and the sampling starts from t = 0. The sampling frequency is 10Hz.

    The samples x(n) (n = 0, 1, 2, ...) are given by

    2. A.
    5(1 - e-0.05n)
    B.
    5e-0.05n
    C.
    5(1 - e-5n)
    D.
    5e-5n

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    Answer : Option B

    Explanation :

    Initial voltage across R = 5Vn

    Final voltage across R = 0V

    Thus VR = 5.0-0.5t

    When we sample this at f∂ = 102

    We get x(n) = .

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