Discussion :: Exam Questions Paper
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In the Taylor series expansion of exp(x) + sin(x) about the point x = p, the coefficient of (x - p)2 is
Answer : Option B
Explanation :
f(x) = ex + sin x
Coefficient of (x - p)2 = 1 / 2! f''(x)
f'(x) = ex + cos x
f'(x) = ex - sin x
f''(x)|x=p = ep
Thus coefficient of (x - p)2 = 0.5 .
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