Consider the following program in Pascal X = 2.57X = (X + 0.06) * 10I = TRUNC (X)X = IX = X / 10.0 The final value of X would be
X = 2.57X = (X + 0.06) * 10I = TRUNC (X)X = IX = X / 10.0
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Answer : Option B
Explanation :
(2.57 + 0.06) 10 = 26.3 → .
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