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  1. For decimal numbe'r 13.5, the floating point representation in 4 byte excess 128 code is

    2. A.
    01101100 00000000 00000000 10000100
    B.
    00000000 01101100 00000000 10000100
    C.
    00000000 01101100 10000100 00000000
    D.
    01101100 00000000 10000100 00000000

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    Answer : Option A

    Explanation :

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