Microwave Communication - ECE Questions and Answers

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If D is diameter of circular waveguide the cutoff wave-length for TE₁₁ mode is equal to

1.706 D

2.11 D

0.82 D

0.41 D

Answer : Option A

Explanation :

Some applications require dual polarization capability. Circular waveguide has this capability.

These analysis uses cylindrical coordinates.

In circular waveguide TE₁₁ mode has the lowest cut off frequency and is the dominant mode.

If D is diameter of waveguide

λ_c = 1.706 D for TE₁₁ mode

λ_c = 1.029 D for TE₂₁ mode

λ_c = 0.82 D for TE₀₁ mode

λ_c = 1.306 D for TM₀₁ mode.

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