Network Analysis and Synthesis - ECE Questions and Answers

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Two voltages are 50 ∠0 V and 75 ∠ - 60° V. The sum of these voltages is

109 ∠ - 60° V

109 ∠ - 25° V

109 ∠ - 36.6° V

100 ∠ - 50.1° V

Answer : Option C

Explanation :

50Ð0 = 50 + j 0.75∠-60° = 37.5 - j 64.95

Sum = (50 + 37.5) - j 64.95 = 87.5 - j 64.95 = 109∠-36.6°

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