Discussion :: Signals and Systems
- The Fourier transform of u(t) is B(jω) & the laplace transform of u(t ) is A(s), then which of the following equation is satisfied
A.
B(jω) = A(s)|s=jω |
B.
A(s) = 1/s but B(jω) ≠1/jω
|
C.
A(s) ≠1/s but B(jω) = 1/jω
|
D.
A(s) ≠1/s but B(jω) ≠1/jω
|
Answer : Option B
Explanation :
Laplace Transform of u(t)
U(t) Ã A(s) = 1/s
Fourier Transform of u(t)
U(t) à B(jω) =( 1/jω) + π δ(ω)
Therefore A(s) = 1/s but B(jω) ≠1/jω is satisfied.
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