Discussion :: Signals and Systems
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If function f(t) has an initial value f(0-) at t = 0-, the Laplace transform of is
Answer : Option A
Explanation :
£f(t) =
£-1F(s) = f(t)
£[a f1(t) + bf2(t)] = aF1(s) + bF2(s)
where
£[f(t - T)] = e-sT F(s)
£[e-at f(t)] = F(s + a)
Initial value theorem
Final value theroem
Convolution Integral
where t is dummy variable for t.
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