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  1. Determine Output:

    #define clrscr() 100
    void main()
    {
          clrscr();
          printf("%d", clrscr());
    }
    2. A.

     0
    B.

     1
    C.

     100
    D.

     Error

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    Workspace

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    Answer : Option C

    Explanation :

    Preprocessor executes as a seperate pass before the execution of the compiler. So textual replacement of clrscr() to 100 occurs. The input program to compiler looks like this :

    void main()
    {
          100;
          printf("%d", 100);
    }

    Note: 100; is an executable statement but with no action. So it doesn't give any problem.

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