Discussion :: Testing New
-
Determine Output:
void main()
{
int i=0;
for(;i++;printf("%d", i));
printf("%d", i);
}
Answer : Option A
Explanation :
Before entering into the for loop checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).
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