Discussion :: Testing New
-
Determine Output:
void main()
{
static int i=5;
if(--i){
main();
printf("%d ", i);
}
}
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Answer : Option B
Explanation :
The variable "i" is declared as static, hence memory for I will be allocated for only once, as it encounters the statement. The function main() will be called recursively unless I becomes equal to 0, and since main() is recursively called, so the value of static I ie., 0 will be printed every time the control is returned.
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