J $ B, B % R, R δ F
Conclusions:
I. F # B
II. R @ J
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Answer : Option E
Explanation :
J $ B -> J >= B
B % R -> B = R
R δ F -> R > F
Therefore, J >= B = R > F
I. F # B -> F < B: True
II. R @ J -> R <= J: True
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