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  1. What will be the output of the program?

    public class RTExcept 
 {    
   public static void throwit ()   
   {       
      System.out.print("throwit ");         
      throw new RuntimeException();
   }   
   public static void main(String [] args) 
   }    
     try       
    {         
        System.out.print("hello ");             
        throwit();     
    }       
    catch (Exception re )     
     {             
        System.out.print("caught ");        
     }        
finally        
    {          
       System.out.print("finally ");        
    }      
   System.out.println("after ");    
  } 
}

    2. A.

    hello throwit caught
    B.

    Compilation fails
    C.

    hello throwit RuntimeException caught after
    D.

    hello throwit caught finally after

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    Answer : Option D

    Explanation :

    The main() method properly catches and handles the RuntimeException in the catch block, finally runs (as it always does), and then the code returns to normal.

    A, B and C are incorrect based on the program logic described above. Remember that properly handled exceptions do not cause the program to stop executing.

     

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