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Discussion :: Operators and Assignments

  1. What will be the output of the program?

    class PassS 
{     
   public static void main(String [] args)      
   {       
       PassS p = new PassS();        
       p. start();    
   }     

   void start()  
   {      
       String s1 = "slip";     
       String s2 = fix(s1);             
       System.out.println(s1 + " " + s2);           
   }    

   String fix(String s1) 
   {       
       s1 = s1 + "stream";         
       System.out.print(s1 + " ");           
       return "stream";   
   } 
}

    2. A.

    slip stream
    B.

    slipstream stream
    C.

    stream slip stream
    D.

    slipstream slip stream

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    View Answer

    Answer : Option D

    Explanation :

    When the fix() method is first entered, start()'s s1 and fix()'s s1 reference variables both refer to the same String object (with a value of "slip"). Fix()'s s1 is reassigned to a new object that is created when the concatenation occurs (this second String object has a value of "slipstream"). When the program returns to start(), another String object is created, referred to by s2 and with a value of "stream".

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