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Discussion :: Operators and Assignments

  1. What will be the output of the program?

    class SSBool
{    
     public static void main(String [] args)     
    {         
       boolean b1 = true;      
       boolean b2 = false;    
       boolean b3 = true;   
      if ( b1 & b2 | b2 & b3 | b2 ) /* Line 8 */ 
           System.out.print("ok "); 
      if ( b1 & b2 | b2 & b3 | b2 | b1 ) /*Line 10*/
           System.out.println("dokey");  
     }
  }

    2. A.

    ok
    B.

    dokey
    C.

    ok dokey
    D.

    No output is produced
    E.

    Compilation error

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    Workspace

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    Answer : Option B

    Explanation :

    The & operator has a higher precedence than the | operator so that on line 8 b1 and b2 are evaluated together as are b2 & b3. The final b1 in line 10 is what causes that if test to be true. Hence it prints "dokey".

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