Discussion :: Threads
-
class Test
{
public static void main(String [] args)
{
printAll(args);}
public static void printAll(String[] lines)
{
for(int i = 0; i{
System.out.println(lines[i]);
Thread.currentThread().sleep(1000);
}
}
}the static method Thread.currentThread() returns a reference to the currently executing Thread object. What is the result of this code?
|
A.
Each String in the array lines will output, with a 1-second pause. |
|
B.
Each String in the array lines will output, with no pause in between because this method is not executed in a Thread. |
|
C.
Each String in the array lines will output, and there is no guarantee there will be a pause because currentThread() may not retrieve this thread. |
|
D.
This code will not compile. |
Whatsapp
Facebook
Answer : Option D
Explanation :
D. The sleep() method must be enclosed in a try/catch block, or the method printAll() must declare it throws the InterruptedException.
A is incorrect, but it would be correct if the InterruptedException was dealt with.
B is incorrect, but it would still be incorrect if the InterruptedException was dealt with because all Java code, including the main() method, runs in threads.
C is incorrect. The sleep() method is static, so even if it is called on an instance, it still always affects the currently executing thread.
Be The First To Comment