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The centre of gravity of an is osceles triangle with base (p) and sides (q) from its base is

$\sqrt \frac { 4p^2 - q^2 } { 6 }$

$\frac { 4p^2 - q^2 } { 6 }$

$\frac {p^2 - q^2 } { 4 }$

$\frac { p^2 + q^2 } { 4 }$

Answer : Option A

Explanation :

No answer description available for this question.

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