Discussion :: Hydraulics and Fluid Mechanics in ME
- A compound pipe of diameter d1, d2 and d3 having lengths l1, l2 and l3 is to be replaced by an equivalent pipe of uniform diameter d and of the same length (l) as that of the compound pipe. The size of the equivalent pipe is given by
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A.
l/d² = (l₁/d₁²) + (l₂/d₂²) + (l₃/d₃²) |
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B.
l/d³ = (l₁/d₁³) + (l₂/d₂³) + (l₃/d₃³) |
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C.
l/d⁴ = (l₁/d₁⁴) + (l₂/d₂⁴) + (l₃/d₃⁴) |
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D.
l/d⁵ = (l₁/d₁⁵) + (l₂/d₂⁵) + (l₃/d₃⁵) |
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Answer : Option D
Explanation :
Explanation Not Provided
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