The loss of head at entrance in a pipe is (where v = Velocity of liquid in the pipe)
\(\frac { v^2 } { 2g }\)
\(\frac {0.5 v^2 } { 2g }\)
\(\frac { 0.375 v^2 } { 2g }\)
\(\frac { 0.75 v^2 } { 2g }\)
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Answer : Option B
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