Hydraulics and Fluid Mechanics - Mechanical Engineering Questions and Answers

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Discussion :: Hydraulics and Fluid Mechanics

A tank of uniform cross-sectional area (A) containing liquid upto height (H₁) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H₁ to H₂ will be

$\frac { 2 A\sqrt{H_1} } { C_d \times a\sqrt{2g} }$

$\frac { 2 A\sqrt{H_2} } { C_d \times a\sqrt{2g} }$

$\frac { 2 A(\sqrt{H_1} - \sqrt{H_2})} { C_d \times a\sqrt{2g} }$

$\frac { 2 A({H_1^\frac{3}{2}} - {H_2^\frac{3}{2}})} { C_d \times a\sqrt{2g} }$

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Answer : Option C

Explanation :

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