Hydraulics and Fluid Mechanics - Mechanical Engineering Questions and Answers

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Discussion :: Hydraulics and Fluid Mechanics

A hemispherical tank of radius (R) containing liquid upto height (H₁) has an orifice of cross-sectional area (a) at its bottom. The time required to lower the level of liquid from (H₁) to (H₂) will be

$\frac { n } { C_d \times a\sqrt{2g} } [\frac {2}{3} R(H_1^\frac{3}{2} - H_2^\frac{3}{2}) - \frac{1}{5}(H_1^\frac{5}{2} - H_2^\frac{5}{2})]$

$\frac { 2n } { C_d \times a\sqrt{2g} } [\frac {2}{3} R(H_2^\frac{3}{2} - H_1^\frac{3}{2}) - \frac{1}{5}(H_2^\frac{5}{2} - H_1^\frac{5}{2})]$

$\frac { 2n } { C_d \times a\sqrt{2g} } [\frac {2}{3} R^2(H_1^\frac{3}{2} - H_2^\frac{3}{2}) - \frac{1}{5}(H_1^\frac{5}{2} - H_2^\frac{5}{2})]$

none of the above

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Answer : Option C

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