Machine Design - Mechanical Engineering Questions and Answers

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When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to

$\frac { 1 } { 2 } \sqrt{M^2+ T^2}$

$\sqrt{M^2 + T^2}$

$\frac { 1 } { 2 } (M + \sqrt{M^2 + T^2})$

$M + \sqrt{M^2 + T^2}$

Answer : Option B

Explanation :

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