When a load W is applied suddenly on a bar of cross-sectional area A, the stress induced in the bar will be
\(\frac { W } { A }\)
\(\frac { W } {2 A }\)
\(\frac { 2 W } { A }\)
\(\frac { 3 W } { A }\)
View Answer
Workspace
Share
Copy Text
Copy URL
Answer : Option C
Explanation :
No answer description available for this question.
Be The First To Comment