Problems on H.C.F and L.C.M - Arithmetic Aptitude Questions and Answers

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The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:

101

107

111

185

Answer : Option C

Explanation :

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

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