Arithmetic Aptitude :: Problems on H.C.F and L.C.M
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Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
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The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
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The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
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Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together ?
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Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
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The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
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Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 2400. Their H.C.F. is:
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The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
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The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:
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ab = 3.
Greater number = 111.