Home / Arithmetic Aptitude / Problems on H.C.F and L.C.M :: Discussion

Discussion :: Problems on H.C.F and L.C.M

  1. The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

  2. A.

    1677

    B.

    1683

    C.

    2523

    D.

    3363

    View Answer

    Workspace

    Answer : Option B

    Explanation :

    L.C.M. of 5, 6, 7, 8 = 840.

     

     Required number is of the form 840k + 3

     

     Least value of k for which (840k + 3) is divisible by 9 is k = 2.

     

     Required number = (840 x 2 + 3) = 1683.

     


Be The First To Comment